ICSE Class 10 Heat — Mock Test (2027)
Free online mock test for Heat (ICSE Class 10 Physics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Heat chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.A metal of mass 250 g is heated to 65°C and then placed in 50 g of water at 20°C. The final steady temperature of the water becomes 25°C. Neglecting the heat taken by the container, what is the specific heat capacity of the metal?
- A.105 J/kg°C
- B.420 J/kg°C
- C.840 J/kg°C
- D.210 J/kg°C
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2.The amount of heat energy required to convert 1 kg of ice at −10°C to water at 100°C is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice = 2100 J kg⁻¹ K⁻¹, specific heat capacity of water = 4200 J kg⁻¹ K⁻¹. Which of the following is the correct value for the specific latent heat of ice?
- A.3,36,000 J kg⁻¹
- B.2,10,000 J kg⁻¹
- C.4,20,000 J kg⁻¹
- D.3,77,000 J kg⁻¹
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3.A copper vessel contains 200 g of water at 24°C. When 112 g of water at 42°C is added, the resultant temperature of the water is 30°C. What is the thermal capacity of the calorimeter?
- A.84.0 J °C⁻¹
- B.100.8 J °C⁻¹
- C.126.0 J °C⁻¹
- D.168.0 J °C⁻¹
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4.A liquid of mass $0.2\,\mathrm{kg}$ and temperature $135^{\circ}\mathrm{C}$ is cooled to $25^{\circ}\mathrm{C}$. If the specific heat capacity of liquid is $750\,\mathrm{J}\,\mathrm{kg}^{-1\,^{\circ}\mathrm{C}^{-1}}$, find the heat energy given out.
- A.16500 J
- B.12000 J
- C.8000 J
- D.20000 J
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5.You are required to make a water bath of $50\,\mathrm{kg}$ at $45^{\circ}\mathrm{C}$, by mixing hot water at $90^{\circ}\mathrm{C}$, with cold water at $20^{\circ}\mathrm{C}$. Calculate the amount of hot water required. Hint: Let amount of hot water $= x$\nHence, Amount of cold water $= (50 - x)\,\mathrm{kg}$
- A.$7.871\,\mathrm{kg}$
- B.$27.871\,\mathrm{kg}$
- C.$17.857\,\mathrm{kg}$
- D.$37.871\,\mathrm{kg}$
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