ICSE Class 10 Force, Turning Effects of Force, and Uniform Circular Motion — Mock Test (2027)
Free online mock test for Force, Turning Effects of Force, and Uniform Circular Motion (ICSE Class 10 Physics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Force, Turning Effects of Force, and Uniform Circular Motion chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.A uniform metre scale of mass 80 g is to be balanced at the 70 cm mark. Find from where a mass of 60 g must be suspended to do so.
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2.The diagram in Fig. 1.28 shows two forces $F_{1} = 5\mathrm{N}$ and $F_{2} = 3\mathrm{N}$ acting at points A and B of a rod pivoted at a point O, such that $\mathrm{OA} = 2\mathrm{m}$ and $\mathrm{OB} = 4\mathrm{m}$.
Calculate:
(i) the moment of force $F_{1}$ about O.
(ii) the moment of force $F_{2}$ about O.
(iii) total moment of the two forces about O. -
3.A fulcrum divides a crow-bar in the ratio 3:1. What weight will be lifted if an effort of 100 N is applied at the end of its longer arm?
- A.400 N
- B.300 N
- C.100 N
- D.500 N
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4.What is the difference between centrifugal and centripetal force?
- A.Centripetal force is a real force acting outward, while centrifugal force is a pseudo force acting inward.
- B.Centripetal force is the real force acting towards the centre of the circular path, while centrifugal force is a pseudo force appearing to act outward in a rotating frame.
- C.Both centripetal and centrifugal forces are real forces acting towards the centre of the circular path.
- D.Centrifugal force is the real force required for circular motion, while centripetal force is an apparent effect in a rotating frame.
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5.The diagram below (Fig. 1.31) shows a uniform bar supported at the middle point O. A weight of $40\mathrm{gf}$ is placed at a distance $40\mathrm{cm}$ to the left of the point O. How can you balance the bar with a weight of $80\mathrm{gf}$?

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