ICSE Class 10 Trigonometric Identities — Mock Test (2027)
Free online mock test for Trigonometric Identities (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Trigonometric Identities chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.Prove the following trigonometric identity by selecting the correct simplified form of the left-hand side (L.H.S.): $\left(\tan A + \frac{1}{\cos A}\right)^2 + \left(\tan A - \frac{1}{\cos A}\right)^2 = ?$
- A.$2 \left(\frac{1 + \sin^2 A}{1 - \sin^2 A}\right)$
- B.$2 \left(\frac{1 + \sin A}{1 - \sin A}\right)$
- C.$2(\tan^2 A + \sec^2 A)$
- D.$\frac{2 \sin^2 A}{\cos^2 A}$
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2.Prove the following trigonometric identity by selecting the correct simplified form of the left-hand side (L.H.S.): $(\operatorname{cosec}A - \sin A)(\sec A - \cos A)(\tan A + \cot A) = ?$
- A.$\frac{\cos^2 A \sin^2 A}{\sin A \cos A} \times \frac{1}{\sin A \cos A} = 1$
- B.$\frac{1 - \sin^2 A}{\sin A} \times \frac{1 - \cos^2 A}{\cos A} \times (\tan A + \cot A) = 1$
- C.$(\cot A)(\tan A)(1) = 1$
- D.$\frac{\cos A}{\sin A} + \frac{\sin A}{\cos A} = 1$
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3.Simplify: $\frac{\csc^2 67^\circ - \cot^2 67^\circ}{\sec^2 20^\circ - \tan^2 20^\circ}$. What is the value of the simplified expression?
- A.0
- B.1
- C.2
- D.1/2
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4.If $m = a \sec A + b \tan A$ and $n = a \tan A + b \sec A$, then which of the following correctly expresses the value of $m^2 - n^2$?
- A.$m^2 - n^2 = a^2 - b^2$
- B.$m^2 - n^2 = (a^2 + b^2)(\sec^2 A - \tan^2 A)$
- C.$m^2 - n^2 = a^2 + b^2$
- D.$m^2 - n^2 = (a + b)^2 - (a - b)^2$
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5.If $\cos 9\alpha = \sin \alpha$ and $9\alpha < 90^\circ$, then the value of $\tan 5\alpha$ is
- a.$\frac{1}{\sqrt{3}}$
- b.$\sqrt{3}$
- c.1
- d.0
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