ICSE Class 10 Electrolysis — Mock Test (2027)
Free online mock test for Electrolysis (ICSE Class 10 Chemistry) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Electrolysis chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.Assertion: During the electrolysis of acidified Copper sulphate solution with Copper electrodes, the size of the cathode decreases. Reason: Copper ions from the electrolyte are deposited on the cathode.
- A.Both assertion and reason are true and reason is the correct explanation of assertion.
- B.Both assertion and reason are true, but reason is not the correct explanation of assertion.
- C.Assertion is true, but reason is false.
- D.Assertion is false, but reason is true.
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2.The ______ the concentration of an ion in a solution, the greater is the probability of it being discharged at its appropriate electrode.
- A.higher
- B.lower
- C.neutral
- D.constant
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3.Molten lead bromide conducts electricity. It is called an _______. It is made up of lead _______ and bromide _______. Which set of terms correctly completes the blanks in order?
- A.electrolyte, cations, anions, positively, cations, negatively, anions
- B.conductor, atoms, molecules, neutrally, atoms, neutrally, molecules
- C.insulator, electrons, protons, negatively, anions, positively, cations
- D.solution, ions, ions, negatively, anions, positively, cations
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4.(iii) Passing of electric current through a conductor results in
- A.physical change
- B.chemical change
- C.both physical and chemical change
- D.None of these
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5.Why does the concentration of sulphuric acid increase at the anode during the electrolysis of acidified water?
- A.H⁺ ions are discharged at the anode, leaving excess SO₄²⁻ ions to form H₂SO₄.
- B.Discharge of OH⁻ ions disturbs the ionic equilibrium of water, causing more water to ionise and produce excess H⁺ ions that combine with SO₄²⁻ ions.
- C.SO₄²⁻ ions are directly oxidized at the anode to form H₂SO₄.
- D.Water molecules split at the anode to release H₂SO₄ directly.
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