ICSE Class 10 Electrolysis — Mock Test (2027)
Free online mock test for Electrolysis (ICSE Class 10 Chemistry) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Electrolysis chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.As we descend the electrochemical series containing cations, the tendency of the cations to get ______ at the cathode increases.
- A.oxidised
- B.reduced
- C.neutralised
- D.vaporised
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2.Assertion: Sodium is obtained at the cathode during the electrolysis of molten Sodium chloride. Reason: Sodium ions gain electrons at the anode during electrolysis.
- A.Both assertion and reason are true and reason is the correct explanation of reason.
- B.Both assertion and are true but reason is not the correct explanation of assertion.
- C.Assertion is true but reason is false.
- D.Assertion is false but reason is true.
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3.When fused lead bromide is electrolysed we observe:
- a.a silver grey deposit at anode and a reddish brown deposit at cathode.
- b.a silver grey deposit at cathode and a reddish brown deposit at anode.
- c.a silver grey deposit at cathode and reddish brown fumes at anode.
- d.silver grey fumes at anode and reddish brown fumes at cathode.
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4.During the electrolysis of sodium chloride, explain the dissociation process and provide the reactions occurring at the cathode and anode. Which of the following correctly represents the overall process and electrode reactions?
- A.NaCl dissociates into Na⁺ and Cl⁻. At the cathode: Na⁺ + e⁻ → Na; at the anode: Cl⁻ - e⁻ → Cl, then Cl + Cl → Cl₂. Overall: 2NaCl → 2Na + Cl₂.
- B.NaCl dissociates into Na⁻ and Cl⁺. At the cathode: Cl⁺ + e⁻ → Cl; at the anode: Na⁻ - e⁻ → Na. Overall: 2NaCl → Na₂ + Cl₂.
- C.NaCl dissociates into Na⁺ and Cl⁻. At the cathode: Cl⁻ + e⁻ → Cl; at the anode: Na⁺ - e⁻ → Na. Overall: NaCl → Na + Cl.
- D.NaCl dissociates into Na and Cl atoms. At the cathode: Na → Na⁺ + e⁻; at the anode: Cl → Cl⁻ - e⁻. Overall: 2NaCl → 2Na⁺ + 2Cl⁻.
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5.In the electrolysis of acidified water, why is dilute sulphuric acid preferred over dilute nitric acid for acidification?
- A.Dilute nitric acid is an oxidising agent and may produce NO, interfering with electrolysis.
- B.Dilute sulphuric acid is a stronger acid and increases ion concentration more effectively.
- C.Dilute nitric acid reacts with water to form a non-conducting solution.
- D.Dilute sulphuric acid prevents the formation of hydrogen gas at the cathode.
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