ICSE Class 10

ICSE Class 10 Trigonometric Identities — Mock Test (2027)

Free online mock test for Trigonometric Identities (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.

What to expect: This mock test covers key concepts from the Trigonometric Identities chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.

Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.

Sample questions

  1. 1.Which of the following simplifies to $\tan A$?
    • A.$\frac{\sin A - 2 \sin^3 A}{2 \cos^3 A - \cos A}$
    • B.$\frac{\sin A + 2 \sin^3 A}{2 \cos^3 A - \cos A}$
    • C.$\frac{2 \sin^3 A - \sin A}{\cos A - 2 \cos^3 A}$
    • D.$\frac{\sin A - 2 \sin^3 A}{\cos A - 2 \cos^3 A}$
  2. 2.Prove the following trigonometric identity by selecting the correct simplified form of the left-hand side (L.H.S.): $(\operatorname{cosec}A - \sin A)(\sec A - \cos A)(\tan A + \cot A) = ?$
    • A.$\frac{\cos^2 A \sin^2 A}{\sin A \cos A} \times \frac{1}{\sin A \cos A} = 1$
    • B.$\frac{1 - \sin^2 A}{\sin A} \times \frac{1 - \cos^2 A}{\cos A} \times (\tan A + \cot A) = 1$
    • C.$(\cot A)(\tan A)(1) = 1$
    • D.$\frac{\cos A}{\sin A} + \frac{\sin A}{\cos A} = 1$
  3. 3.(iii) Using tables find the value of: $\tan 31^\circ 27'$
    • A.0.6084
    • B.0.6104
    • C.0.6116
    • D.0.6146
  4. 4.Which of the following correctly completes the proof that $(\sin A + \cos A)(\sec A + \csc A) = 2 + \sec A \csc A$?
    • A.$(\sin A + \cos A)(\sec A + \csc A) = \tan A + \cot A + 2$
    • B.$(\sin A + \cos A)(\sec A + \csc A) = \sin A \cos A + \sec A \csc A$
    • C.$(\sin A + \cos A)(\sec A + \csc A) = 1 + \sec A + \csc A$
    • D.$(\sin A + \cos A)(\sec A + \csc A) = 2 \tan A + 2 \cot A$
  5. 5.Eliminate θ from the following equations: $a \cot \theta + b \csc \theta = x$ and $a \csc \theta + b \cot \theta = y$. Which of the following relations is obtained?
    • A.$b^2 - a^2 = x^2 - y^2$
    • B.$a^2 - b^2 = x^2 - y^2$
    • C.$a^2 + b^2 = x^2 + y^2$
    • D.$x^2 - y^2 = 2ab$

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