ICSE Class 10 Ratio and Proportion — Mock Test (2027)
Free online mock test for Ratio and Proportion (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Ratio and Proportion chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.Using properties of proportion, solve for $x$. Given that $x$ is positive. $$ \frac{2x + \sqrt{4x^2 - 1}}{2x - \sqrt{4x^2 - 1}} = 4 $$
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2.Two numbers are in the ratio $5:7$. If 8 is subtracted from each, the ratio becomes $3:5$. Which of the following pairs represents the original numbers?
- A.15 and 21
- B.20 and 28
- C.10 and 14
- D.25 and 35
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3.Solve the equation: $\frac{\sqrt{x + 5} + \sqrt{x - 16}}{\sqrt{x + 5} - \sqrt{x - 16}} = \frac{7}{3}$. What is the value of $x$?
- A.16
- B.20
- C.25
- D.41
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4.If $a : b = 5 : 3$, find the value of $(5a + 8b) : (6a - 7b)$.
- A.49 : 9
- B.25 : 9
- C.49 : 3
- D.15 : 7
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5.If $\frac{a}{b} = \frac{c}{d}$, which of the following correctly shows that $\frac{ma + nb}{mc + nd} = \frac{ma - nb}{mc - nd}$?
- A.By applying alternendo and componendo-dividendo to the given proportion, the equality is proved.
- B.Cross-multiplying the given proportion yields $ad = bc$, which directly proves the equality.
- C.Adding and subtracting $ma$ and $nb$ on both sides of the proportion proves the result.
- D.The equality holds because $\frac{ma + nb}{mc + nd} = \frac{a}{c}$ and $\frac{ma - nb}{mc - nd} = \frac{b}{d}$.
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