ICSE Class 10 Linear Inequations (in one variable) — Mock Test (2027)
Free online mock test for Linear Inequations (in one variable) (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Linear Inequations (in one variable) chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.The sets $A = \{x: 11x - 5 > 7x + 3, x \in \mathbb{R}\}$ and $B = \{x: 18x - 9 \geq 15 + 12x, x \in \mathbb{R}\}$ are represented on the number line below.
Which labeled part on the number line correctly represents the range of $A \cap B$?- A.The ray starting at 2 and extending to the right, including 2.
- B.The ray starting at 4 and extending to the right, including 4.
- C.The ray starting at 2 and extending to the right, excluding 2.
- D.The segment between 2 and 4, including both endpoints.
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2.The diagram below shows a number line representing the range of values of $x$ which satisfies the inequality $-2\frac{2}{3} \leq x + \frac{1}{3} < 3\frac{1}{3}, x \in \mathbb{R}$. Which labeled part on the number line correctly corresponds to the solution of this inequality?

- A.A closed circle at -3 and an open circle at 3
- B.An open circle at -3 and a closed circle at 3
- C.A closed circle at -8/3 and an open circle at 10/3
- D.Closed circles at both -3 and 3
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3.Solve the following inequation and select the correct solution set from the options below: (-x)/3 ≤ x/2 - 1 1/3 < 1/6, x ∈ R.

- A.{x: 1.6 ≤ x < 3, x ∈ R}
- B.{x: x ≤ 1.6 or x > 3, x ∈ R}
- C.{x: 1.6 < x ≤ 3, x ∈ R}
- D.{x: x < 1.6 or x ≥ 3, x ∈ R}
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4.If $\frac{5 - 2x}{7} < \frac{x}{7} - 5$ then
- A.$x > 8$
- B.$x < 8$
- C.$x \leq 8$
- D.$x \geq 8$
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5.Solve the following inequation and select the correct solution set from the options below. Represent it on the number line: $-3(x - 7) \geq 15 - 7x > \frac{x + 1}{3}, x \in R$.

- A.$\{x: -1.5 < x \leq 2, x \in R\}$
- B.$\{x: -1.5 \leq x < 2, x \in R\}$
- C.$\{x: x \geq -1.5 \text{ or } x < 2, x \in R\}$
- D.$\{x: x < -1.5 \text{ and } x \geq 2, x \in R\}$
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